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Question Number 199351 by Tawa11 last updated on 01/Nov/23

Answered by MM42 last updated on 02/Nov/23

$$a+b=2$$$${{\int }_0^4(a\sqrt{x}+bx)dx=\frac{2a}{3}x\sqrt{x}+\frac{b}{2}{x}^2]}_0^4=8$$$$\Rightarrow \frac{16}{3}a+8b=8-8a$$$$\Rightarrow a=3\mathrm{\&}b=-1✓\left(c\right),\left(d\right)$$$$$$

Commented by Tawa11 last updated on 19/Nov/23

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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