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Question Number 199433 by ajfour last updated on 03/Nov/23

Commented by ajfour last updated on 03/Nov/23

$O u t e r f i g u r e i s s q u a r e o f s i d e a .$ $C o l o u r e d t r i a n g l e s a r e e q u i l a t e r a l .$ $F i n d r a d i u s o f c i r c l e i n s c r i b e d .$
	Answered by mr W last updated on 03/Nov/23

	Commented by mr W last updated on 03/Nov/23

	$\frac{r}{\sin 30 °} = \frac{a}{2 \sin 75 °}$ $\Rightarrow r = \frac{a}{4 \cos 15 °} = \frac{a}{\sqrt{6} + \sqrt{2}} = \frac{(\sqrt{6} - \sqrt{2}) a}{4}$
	Commented by ajfour last updated on 03/Nov/23

	$y e s, t h a n k s s i r, a m o u n t s t o s a m e ✓$
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