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Question Number 199480 by Abdullahrussell last updated on 04/Nov/23

Commented by mr W last updated on 04/Nov/23

=((sin θ+sin 50°+1+sin 50°)/(cos θ+cos 50°+0−cos 50°))  =((sin θ+1+2 sin 50°)/(cos θ))

=sinθ+sin50°+1+sin50°cosθ+cos50°+0cos50°=sinθ+1+2sin50°cosθ

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