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Question Number 199486 by hardmath last updated on 04/Nov/23

Solve:   100^x  = 200

Solve:100x=200

Answered by cortano12 last updated on 04/Nov/23

log _(10) (100^x )= log _(10) (200)    2x = 2+log _(10) (2)     x=1+log _(10) ((√2) )

log10(100x)=log10(200)2x=2+log10(2)x=1+log10(2)

Answered by Skabetix last updated on 04/Nov/23

xln(100)=ln(200)  x=((ln(200))/(ln(100)))=((log(200))/2)

xln(100)=ln(200)x=ln(200)ln(100)=log(200)2

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