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Question Number 199510 by universe last updated on 04/Nov/23

	Answered by mr W last updated on 06/Nov/23

	Commented by mr W last updated on 06/Nov/23

	$s e t F = m i d p o i n t o f E B$ $E D / / F C$ $\frac{y}{x} = \frac{A E}{E F} = \frac{E B}{E F} = \frac{2}{1} = 2 ✓$
	Answered by deleteduser1 last updated on 04/Nov/23

	$L e t D E a n d C B m e e t a t F; j o i n A F; i n t r i a n g l e$ $A F B; \Rightarrow L i n e A C a n d F E a r e m e d i a n s$ $\Rightarrow D i s t h e c e n t r o i d \Rightarrow \frac{A D}{D C} = 2$
	Answered by mr W last updated on 04/Nov/23

	Commented by mr W last updated on 04/Nov/23

	$\frac{y}{x} = \frac{A F}{E C} = \frac{A B}{E B} = \frac{2}{1} = 2 ✓$
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