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Question Number 199708 by tri26112004 last updated on 08/Nov/23

$$n^{20}+{11}^n=2023(n\in N)$$$$n=¿$$

Commented by Rasheed.Sindhi last updated on 08/Nov/23

$$f\left(n\right)=n^{20}+{11}^n\left(increasingfunction\right)$$$$f\left(1\right)=12$$$$f\left(k\right)=2023$$$$f\left(2\right)=1048697$$$$f\left(1\right)<f\left(k\right)<f\left(2\right)$$$$1<k<2$$$$\mathcal{T}{here}^{\prime }snonaturalbetween1\mathrm{\&}2.$$

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