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Question Number 199753 by sonukgindia last updated on 08/Nov/23

Answered by MM42 last updated on 09/Nov/23

let  :  f=xsinx+cosx  &  g=xcosx+sinx  f=g  ⇒^(0≤x≤1)  x=1 ,(π/4)  ⇒s=∣∫_0 ^(π/4) (f−g)dx∣+∣∫_(π/4) ^1 (f−g)dx ∣  =2(√2)−((√2)/2)π+cos1−sin1  ✓

let:f=xsinx+cosx&g=xcosx+sinxf=g0x1x=1,π4s=∣0π4(fg)dx+π41(fg)dx=2222π+cos1sin1

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