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Question Number 199753 by sonukgindia last updated on 08/Nov/23
Answered by MM42 last updated on 09/Nov/23
let:f=xsinx+cosx&g=xcosx+sinxf=g⇒0⩽x⩽1x=1,π4⇒s=∣∫0π4(f−g)dx∣+∣∫π41(f−g)dx∣=22−22π+cos1−sin1✓
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