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Question Number 199774 by Mingma last updated on 09/Nov/23

Answered by ajfour last updated on 09/Nov/23

Commented by ajfour last updated on 09/Nov/23

$$P(perimeterof△ABC)$$$$=2R+2R\cos \theta$$$$leftpartofitcutbyMN$$$$=BM+BN(=AB)$$$$=R\cos \theta +R=\frac{P}{2}$$$$S(Area△ABC)=R^2\sin \theta \cos \theta$$$$areacutbyMN=\frac{BM}{2}\times MN$$$$=\frac{R\cos \theta }{2}\times R\sin \theta =\frac{S}{2}$$

Commented by Mingma last updated on 09/Nov/23

Very elegant solution!

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