Question and Answers Forum

All Questions      Topic List

Logarithms Questions

Previous in All Question      Next in All Question      

Previous in Logarithms      Next in Logarithms      

Question Number 199801 by Calculusboy last updated on 09/Nov/23

Answered by Frix last updated on 09/Nov/23

$$x=a\sqrt{b-a\sqrt{b-a\sqrt{b-...}}}$$$$x=a\sqrt{b-x}$$$$x^2=a^2(b-x)$$$$x^2+a^{2}x-a^{2}b=0$$$$x=-\frac{a^2}{2}+\frac{a^2\sqrt{a^2+4b}}{2}$$$$a=\frac{\sqrt{2}}{6}\wedge b=4$$$$x=\frac{4}{9}$$$$6+\frac{\ln \frac{4}{9}}{\ln \frac{3}{2}}=6-2=4$$

Commented by Calculusboy last updated on 10/Nov/23

$$\mathit{t}\mathit{h}\mathit{a}\mathit{n}\mathit{k}\mathit{s}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com