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Question Number 199825 by cortano12 last updated on 10/Nov/23

Answered by mr W last updated on 10/Nov/23

Commented by mr W last updated on 10/Nov/23

$$\alpha =2\theta$$$$\beta =2\varphi$$$$p=2R\sin \frac{\alpha }{2}=2R\sin \theta$$$$q=2R\sin \frac{\beta }{2}=2R\sin \varphi =2R\cos \theta$$$$p^2+q^2={\left(2R\right)}^2({\sin }^2\theta +{\cos }^2\theta )={\left(2R\right)}^2$$

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