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Question Number 199838 by Calculusboy last updated on 10/Nov/23

Answered by Frix last updated on 10/Nov/23

$$y=\sqrt[x]{xy}$$$$y=x^{\frac{1}{x-1}}$$$${(x+5)}^x=23x+1+x^{\frac{1}{x-1}}$$$$\mathrm{Trying}x=1,2,3$$$$\Rightarrow x=2$$$$\underset{i=-1}{\sum ^n}\frac{4i+7}{4^{i+1}}=\frac{52}{9}-\frac{(12n+37)}{4^{n}36}$$$$E=\underset{i=-1}{\sum ^{\mathrm{\infty }}}\frac{4i+7}{4^{i+1}}=\frac{52}{9}$$

Commented by Calculusboy last updated on 11/Nov/23

$$\mathit{t}\mathit{h}\mathit{a}\mathit{n}\mathit{k}\mathit{s}\mathit{s}\mathit{i}\mathit{r}$$

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