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Question Number 199952 by Abdullahrussell last updated on 11/Nov/23

Answered by cortano12 last updated on 11/Nov/23

$$=\frac{2\sin 7\theta \cos 2\theta +2\sin 7\theta \cos 6\theta }{2\cos 7\theta \cos 2\theta +2\cos 7\theta \cos 6\theta }$$$$=\frac{\sin 7\theta (\cos 2\theta +\cos 6\theta )}{\cos 7\theta (\cos 2\theta +\cos 6\theta )}$$$$=\tan 7\theta$$

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