(2+(π/e))(((17)/(16))+(π/(4e)))(((82)/(81))+(π/(9e)))(((257)/(256))+(π/(16e)))...


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Question Number 133988 by Dwaipayan Shikari last updated on 26/Feb/21

$(2 + \frac{π}{e}) (\frac{17}{16} + \frac{π}{4 e}) (\frac{82}{81} + \frac{π}{9 e}) (\frac{257}{256} + \frac{π}{16 e}) . . .$
Commented by Olaf last updated on 26/Feb/21

$P = \underset{n = 1}{\prod^{\infty}} (\frac{? + 1}{?} + \frac{π}{n^{2} e})$ $. . . I {c a n}^{'} t f i n d t h e s e q u e n c e . . .$ $. . . n o t e n o u g h d a t a . . .$
Commented by Dwaipayan Shikari last updated on 26/Feb/21

$\underset{n = 1}{\prod^{\infty}} (1 + \frac{1}{n^{4}} + \frac{π}{{e n}^{2}}) . S o r r y i h a v e e d i t e d$
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