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Question Number 200336 by deleteduser12 last updated on 17/Nov/23

Answered by cortano12 last updated on 17/Nov/23

$$\overline{)\begin{array}{ccccccc}& 1& 2& -3& 5& -2& 3\\ \mathrm{x}=2& \ast & 2& 8& 10& 30& 56\\ & 1& 4& 5& 15& 28& 59\end{array}}$$$$\mathrm{the}\mathrm{remainder}\mathrm{is}59$$$$\mathrm{the}\mathrm{quotient}\mathrm{is}\mathrm{h}\left(\mathrm{x}\right)={\mathrm{x}}^4+{4\mathrm{x}}^3+{5\mathrm{x}}^2+15\mathrm{x}+28$$

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