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Question Number 200351 by deleteduser12 last updated on 17/Nov/23

$$\mathrm{Solve}\mathrm{the}\mathrm{equation}{\mathrm{x}}^3-{12\mathrm{x}}^2-6\mathrm{x}-10=0$$$$\mathrm{by}{\mathrm{cardon}}^{\prime }\mathrm{s}\mathrm{method}$$

Answered by Frix last updated on 17/Nov/23

$$\mathrm{The}\mathrm{name}\mathrm{is}Cardano$$$$x^3-12x^2-6x-10=0$$$$x=t+4$$$$t^3-54t-162=0$$$$t=3\sqrt[3]{2}(1+\sqrt[3]{2})$$$$x=4+3\sqrt[3]{2}(1+\sqrt[3]{2})$$

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