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Question Number 200379 by cortano12 last updated on 18/Nov/23
Commented by Frix last updated on 18/Nov/23
Noexactsolutionspossible.Transformto{y2+x2+x+12(x+1)y+x2+x−204(x+1)=0y2+x2+6x+62x(x+1)y+3x−202x(x+1)=0Subtractandsolveforyy=−(x−2)(x2+3x−20)2(x3−5x−6)Insertandtransformx6−35x5+34x4+500x3−784x2−680x+560=0Thishasgot6realsolutions...
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