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Question Number 200403 by Anonim_X last updated on 18/Nov/23
∫(x2+1)dxx(x−1)(x+1)=??
Answered by cortano12 last updated on 18/Nov/23
I=∫x2−1+2x(x−1)(x+1)dxI=ln∣x∣+2∫dxx(x+1)(x−1)I=ln∣x∣+2∫(−1x+12(x+1)+12(x−1))dxI=−ln∣x∣+ln∣x+1∣+ln∣x−1∣+c
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