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Question Number 200420 by ajfour last updated on 18/Nov/23

Commented by ajfour last updated on 18/Nov/23

plz solve..

plzsolve..

Commented by ajfour last updated on 18/Nov/23

Find a and b.

Findaandb.

Commented by deleteduser1 last updated on 18/Nov/23

(√(1−(b−a)^2 ))+(√(a^2 −(b−a)^2 ))=a+(2/3) [a+(2/3)−(√(2ba−b^2 ))][a+(2/3)]=1×[1+x]...(i) (√(a^2 −x^2 ))=y=(√(1^2 −(b−x)^2 ))⇒a^2 =1−b^2 +2bx...(ii) (i)∧(ii)⇒a^2 +(4/3)a+(4/9)−a(√(2ba−b^2 ))−(2/3)(√(2ba−b^2 ))−1=x =((a^2 +b^2 −1)/(2b))[This is the relationship between a&b]

1−(b−a)2+a2−(b−a)2=a+23[a+23−2ba−b2][a+23]=1×[1+x]...(i)a2−x2=y=12−(b−x)2⇒a2=1−b2+2bx...(ii)(i)∧(ii)⇒a2+43a+49−a2ba−b2−232ba−b2−1=x=a2+b2−12b[Thisistherelationshipbetweena&b]

Commented by mr W last updated on 18/Nov/23

impossible figure! triangle with sides: 1, a, 1+a

impossiblefigure!trianglewithsides:1,a,1+a

Commented by deleteduser1 last updated on 18/Nov/23

Exactly,the triangle has to be a line.

Exactly,thetrianglehastobealine.

Commented by ajfour last updated on 18/Nov/23

yeah sorry, lets have instead of the side a+1 we have a+(2/3) .

yeahsorry,letshaveinsteadofthesidea+1wehavea+23.

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