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Question Number 200438 by hardmath last updated on 18/Nov/23

$$\mathrm{Find}:$$$$\sqrt{3+\sqrt{6+\sqrt{9+...+\sqrt{96+\sqrt{99}}}}}=?$$

Commented by Frix last updated on 19/Nov/23

$${\mathrm{There}}^{\prime }\mathrm{s}\mathrm{nothing}\mathrm{to}\mathrm{find},\mathrm{just}\mathrm{use}\mathrm{a}\mathrm{good}$$$$\mathrm{calculator}.$$

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