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Question Number 200617 by sonukgindia last updated on 21/Nov/23

Answered by Frix last updated on 21/Nov/23

$$x+a=y^2$$$$y+a=x^2$$$$x-y=y^2-x^2$$$$x^2-y^2+x-y=0$$$$(x-y)(x+y)+(x-y)=0$$$$(x-y)(x+y+1)=0$$$$y=x\vee y=-(x+1)$$$$\mathrm{Now}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{easy}\mathrm{to}\mathrm{do}\mathrm{the}\mathrm{rest}.$$

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