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Question Number 200716 by hardmath last updated on 22/Nov/23

1. (a/8) + (b/5) = 6 ⇒ (a+b)_(max) = ?

1.a8+b5=6⇒(a+b)max=?

Answered by deleteduser1 last updated on 22/Nov/23

5a+8b=240⇒a=((240−8b)/5) remains to find (a+b)_(max) =(((240−3b)/5))_(max) If b≥0, then max(a+b)=((240)/5)=48 But if b can be less than 0,then a+b has no upper bound

5a+8b=240⇒a=240−8b5remainstofind(a+b)max=(240−3b5)maxIfb⩾0,thenmax(a+b)=2405=48Butifbcanbelessthan0,thena+bhasnoupperbound

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