Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 200748 by Rupesh123 last updated on 22/Nov/23

Answered by MM42 last updated on 22/Nov/23

$${s=4{\int }_0^c(c^2-x^2)dx=4(c^{2}x-\frac{1}{3}{x}^3)]}_0^c$$$$=4(c^3-\frac{1}{3}{c}^3)=\frac{8}{3}{c}^3=\frac{64}{3}\Rightarrow c=2✓$$

Answered by cortano12 last updated on 23/Nov/23

$$\iff {2\mathrm{x}}^2-{2\mathrm{c}}^2=0$$$$\iff \frac{64}{3}=\frac{{16\mathrm{c}}^2.4\mathrm{c}}{6.4}$$$$\Rightarrow 64={8\mathrm{c}}^3;\mathrm{c}=2$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com