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Question Number 200788 by hardmath last updated on 23/Nov/23

$$\sin \mathbf{x}+\cos \mathbf{x}=\mathrm{tg}\mathbf{x}$$$$\mathrm{x}=?$$

Answered by Frix last updated on 23/Nov/23

$$x={2\tan }^{-1}t\mathrm{leads}\mathrm{to}$$$$t^4-4t^3-2t^2+1=0$$$$\mathrm{No}\mathrm{nice}\mathrm{solution}.$$$$t_1\approx .513620$$$$t_2\approx 4.43911$$$$x_1\approx .948968+2n\pi$$$$x_2=2.69845+2n\pi$$

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