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Question Number 200816 by mr W last updated on 23/Nov/23

Commented by mr W last updated on 23/Nov/23

$f i n d t h e c o l o r e d a r e a s .$
Commented by Ari last updated on 24/Nov/23

$e x c u s e m e a r e t h e s e g m e n t f r o m v e r t i c e s$ $h a l f o f t h e a n g l e s ?$
Commented by mr W last updated on 24/Nov/23

$n o t s u r e . o n l y t h e a r e a s a r e g i v e n .$
	Answered by deleteduser1 last updated on 24/Nov/23

	$\frac{A D}{D B} = \frac{[A G D]}{[G D B]} = \frac{4}{3}; L e t [C G F] = r \land [G E A] = s$ $\frac{84}{s} \times \frac{4}{3} \times \frac{35}{r} = 1 \Rightarrow r s = 3920$ $\frac{[A F C]}{[A B F]} = \frac{84 + r + s}{105} = \frac{r}{35} \Rightarrow 2 r = 84 + \frac{3920}{r}$ $\Rightarrow 2 r^{2} - 84 r - 3920 = 0 \Rightarrow r = 70 \Rightarrow s = 56$
	Commented by deleteduser1 last updated on 24/Nov/23

	Commented by mr W last updated on 24/Nov/23

	$y e s . t h a n k s!$
	Answered by mr W last updated on 24/Nov/23

	$\frac{84 + y}{40} = \frac{b + 35}{30}$ $\Rightarrow 3 y - 4 b = - 112 . . . (i)$ $\frac{40 + 30}{35} = \frac{84 + y}{b}$ $\Rightarrow y - 2 b = - 84 . . . (i i)$ $\Rightarrow y = 56 = y e l l o w a r e a$ $\Rightarrow b = 70 = b l u e a r e a$
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