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Question Number 200821 by Calculusboy last updated on 24/Nov/23

Answered by shunmisaki007 last updated on 24/Nov/23

$$\ln (10!)$$$$=\ln (10\cdot 9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1)$$$$=\ln ((2\cdot 5)\cdot 3^2\cdot 2^3\cdot 7\cdot (2\cdot 3)\cdot 5\cdot 2^2\cdot 3\cdot 2\cdot 1)$$$$=\ln (2^8\cdot 3^4\cdot 5^2\cdot 7)$$$$=8\ln \left(2\right)+4\ln \left(3\right)+2\ln \left(5\right)+\ln \left(7\right)...★$$

Commented by Calculusboy last updated on 26/Nov/23

$$\mathit{t}\mathit{h}\mathit{a}\mathit{n}\mathit{k}\mathit{s}\mathit{s}\mathit{i}\mathit{r}$$

Commented by Calculusboy last updated on 26/Nov/23

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