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Question Number 200840 by Rydel last updated on 24/Nov/23
limx→axnsina−ansinxx−a
Answered by MM42 last updated on 24/Nov/23
limx→axnsina−ansina+ansina−ansinxx−a=limx→a(xn−an)sina−(sinx−sina)anx−a=limx→a((x−a)(xn−1+xn−1a+...+an−1)sinax−a−2sin(x−a2)x−a×cos(x+a2)×an)=nan−1sina−cosa✓
Commented by Rydel last updated on 24/Nov/23
thankyouverymuch
Answered by BaliramKumar last updated on 24/Nov/23
limx→addx(xnsina−ansinx)ddx(x−a)=nxn−1sina−ancosx1nan−1sina−ancosa=an(nsina−acosa)a
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