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Question Number 200864 by Rydel last updated on 25/Nov/23

$$\underset{x\to +\mathrm{\infty }}{\lim }\frac{xE\left(x\right)+3}{\sqrt{x^2+\sin x}}$$

Answered by Mathspace last updated on 25/Nov/23

$$={lim}_{x\to +\mathrm{\infty }}\frac{xE\left(x\right)+3}{x\sqrt{1+\frac{sinx}{x^2}}}$$$$={lim}_{x\to +\mathrm{\infty }}\frac{E\left(x\right)+\frac{3}{x}}{\sqrt{1+\frac{sinx}{x^2}}}$$$$={lim}_{x\to +\mathrm{\infty }}E\left(x\right)=+\mathrm{\infty }$$

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