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Question Number 200972 by Mingma last updated on 27/Nov/23

Answered by deleteduser1 last updated on 27/Nov/23

$$a^2=b^2(b+2);a=b\sqrt{b+2}$$$$b={\left(\frac{x}{y}\right)}^2-2\Rightarrow (a,b)=(\frac{x^3-2{xy}^2}{y^3},\frac{x^2}{y^2}-2)forx,y\in \mathbb{Z}$$

Commented by Mingma last updated on 27/Nov/23

very elegant!

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