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Question Number 201166 by mnjuly1970 last updated on 01/Dec/23

Answered by mr W last updated on 01/Dec/23

((ah)/2)=4  ⇒h=((2×4)/( (√2)))=4(√2)  h×cot B+h×cot C=a  ⇒cot B+cot C=(a/h)=((√2)/(4(√2)))=(1/4)

ah2=4h=2×42=42h×cotB+h×cotC=acotB+cotC=ah=242=14

Commented by mnjuly1970 last updated on 01/Dec/23

   bravo sir thanks alot ... ⋛

bravosirthanksalot...

Commented by mr W last updated on 01/Dec/23

Commented by mr W last updated on 01/Dec/23

a_1 =h cot B  a_2 =h cot C  a=a_1 +a_2 =h(cot B+cot C)  S=((ah)/2)=(a^2 /(2(cot B+cot C)))  ⇒cot B+cot C=(a^2 /(2S))=((((√2))^2 )/(2×4))=(1/4)

a1=hcotBa2=hcotCa=a1+a2=h(cotB+cotC)S=ah2=a22(cotB+cotC)cotB+cotC=a22S=(2)22×4=14

Commented by mnjuly1970 last updated on 01/Dec/23

so nice master .grateful

sonicemaster.grateful

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