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Question Number 201460 by hardmath last updated on 06/Dec/23

Find the smallest positive period of the  function:  y = ∣ tan 2x ∣  +  ∣ cot 2x ∣

Findthesmallestpositiveperiodofthefunction:y=tan2x+cot2x

Answered by Mathspace last updated on 07/Dec/23

y(x)=∣tan(2x)∣+(1/(∣tan(2x)∣))  y(x+(π/2))=∣tan(2(x+(π/2)))+(1/(∣tan(2(x+(π/2)))))  =∣tan(2x+π)∣+(1/(∣tan(2x+π)∣))  =∣tan(2x)∣+(1/(∣tan(2x)∣))  =f(x) so the small period is  T=(π/2)

y(x)=∣tan(2x)+1tan(2x)y(x+π2)=∣tan(2(x+π2))+1tan(2(x+π2))=∣tan(2x+π)+1tan(2x+π)=∣tan(2x)+1tan(2x)=f(x)sothesmallperiodisT=π2

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