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Question Number 201562 by Mingma last updated on 09/Dec/23

Answered by mr W last updated on 09/Dec/23

$$r=radiusofquartercircle$$$$a=sidelengthofsquare$$

Commented by mr W last updated on 09/Dec/23

Commented by mr W last updated on 09/Dec/23

$$r^2={(\frac{a}{\sqrt{2}}+\frac{a}{\sqrt{2}})}^2+{\left(\frac{a}{\sqrt{2}}\right)}^2=\frac{5a^2}{2}$$$$\Rightarrow a^2=\frac{2r^2}{5}=0.4=areaofsquare$$

Commented by Mingma last updated on 09/Dec/23

Perfect ��

Answered by cherokeesay last updated on 09/Dec/23

Commented by Mingma last updated on 09/Dec/23

Perfect ��

Answered by ajfour last updated on 09/Dec/23

Commented by ajfour last updated on 09/Dec/23

$${(a+\frac{a}{2})}^2+{\left(\frac{a}{2}\right)}^2=1$$$$a^2=\frac{4}{10}=0.4$$

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