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Question Number 201798 by hardmath last updated on 12/Dec/23

$$\mathrm{Find}\mathrm{the}\mathrm{differential}\mathrm{of}\mathrm{the}\mathrm{function}:$$$$\mathbf{y}=\sqrt{{\mathbf{x}}^2-1}$$

Answered by dimentri last updated on 12/Dec/23

$$y=\sqrt{x^2-1}\Rightarrow y^{\prime }=\frac{x}{\sqrt{x^2-1}}=\frac{x}{y}$$$${yy}^{\prime }-x=0$$

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