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Question Number 201822 by MathedUp last updated on 13/Dec/23

Do Not Use sin(θ)∼θ (θ  is small Enough)  θ^  +(g/ℓ)sin(θ)=0  y′′(t)+(g/ℓ) sin(y(t))=0  y′′(t)y′(t)+(g/ℓ)sin(y(t))y′(t)=0  y′(t)y′′(t)=(1/2)∙((d  )/dt)(y′(t))^2   (g/ℓ)sin(y(t))y′(t)=−(g/ℓ)∙((d  )/dt)cos(y(t))  ∴ ((d  )/dt)[(1/2)(y′(t))^2 −(g/ℓ)cos(y(t))]=0  ∴(1/2)(y′(t))^2 −(g/ℓ)cos(y(t))=c_1   Const  y′′(t)+(g/ℓ)sin(y(t))=0→(y′(t))^2 −((2g)/ℓ)cos(y(t))=c_1   and... I can′t Sove Diff  Equa..

DoNotUsesin(θ)θ(θissmallEnough)θ¨+gsin(θ)=0y(t)+gsin(y(t))=0y(t)y(t)+gsin(y(t))y(t)=0y(t)y(t)=12ddt(y(t))2gsin(y(t))y(t)=gddtcos(y(t))ddt[12(y(t))2gcos(y(t))]=012(y(t))2gcos(y(t))=c1Consty(t)+gsin(y(t))=0(y(t))22gcos(y(t))=c1and...IcantSoveDiffEqua..

Commented by mr W last updated on 13/Dec/23

Commented by mr W last updated on 13/Dec/23

Commented by mr W last updated on 14/Dec/23

not only you, but all people in the  world can not solve it using elementary  functions. to find the period  you   can apply elliptic integrals.

notonlyyou,butallpeopleintheworldcannotsolveitusingelementaryfunctions.tofindtheperiodyoucanapplyellipticintegrals.

Commented by MathedUp last updated on 14/Dec/23

  Thank you a lot

Thankyoualot

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