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Question Number 201853 by sonukgindia last updated on 14/Dec/23

	Answered by deleteduser1 last updated on 14/Dec/23

	$L e t g r e e n s e g m e n t = g; o r a n g e s e g m e n t = r$ $a n d b l u e s e g m e n t = b; s i d e o f s q u a r e = s$ $\frac{b}{r} = \frac{7 - 5}{7 - 3} \Rightarrow r = 2 b; \frac{g}{g + s} = \frac{2}{4} \Rightarrow g = s$ $\frac{2 b}{2 b + s} = \frac{7 - 3}{13 - 3} = \frac{2}{5} \Rightarrow 5 r = 2 r + 2 s \Rightarrow r = \frac{2 s}{3}$ $r^{2} + {(s + g)}^{2} = 16 \Rightarrow \frac{4 s^{2}}{9} + 4 s^{2} = 16 \Rightarrow 40 s^{2} = 16 \times 9$ $\Rightarrow s^{2} = \frac{4 \times 9}{10} = 3.6$
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