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Question Number 201864 by ajfour last updated on 14/Dec/23
(ct2−1ct2+2)2=c2(t4+1t4)Findt=f(c).
Commented by Frix last updated on 14/Dec/23
Thisisequivalentto(t2)3−(t2)c2+2(1−c4)4c3=0whichcanbesolved(methoddependingonthevalueof27c8−54c4−5)
Commented by ajfour last updated on 14/Dec/23
Thanks,c4=1−22p&p2<427Sirhowwouldyoudothis:x4−9x2+6x−1=0Ifiguedoutanicewayforsuchc2=4bdholdingbiquadratics.
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