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Question Number 201906 by sonukgindia last updated on 15/Dec/23

Answered by deleteduser1 last updated on 15/Dec/23

$$sin\left(x\right)=\frac{s}{h}...\left(i\right)$$$$\left(ii\right)...\frac{sin\left(2x\right)}{h}=\frac{sin\left(x\right)}{2s}\Rightarrow 2sin\left(x\right)=\frac{sin\left(x\right)}{sin\left(2x\right)}$$$$\Rightarrow sin\left(2x\right)=\frac{1}{2}\Rightarrow x=15°$$

Answered by mr W last updated on 16/Dec/23

Commented by mr W last updated on 16/Dec/23

$$AB=BC=2\times BE$$$$\sin 2\alpha =\frac{BE}{AB}=\frac{1}{2}$$$$\Rightarrow 2\alpha =30°\Rightarrow \alpha =15°$$

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