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Question Number 201925 by Calculusboy last updated on 15/Dec/23

Commented by Calculusboy last updated on 17/Dec/23

thanks sir

thankssir

Commented by Frix last updated on 16/Dec/23

=2∫_0 ^(π/4) (((1+tan^2  x)^2 )/(1−tan x +tan^2  x −tan^3  x +tan^4  x))dx  Use t=tan x to get  2∫_0 ^1 ((t^2 +1)/(t^4 −t^3 +t^2 −t+1))dt  I get ((2(√(5(5+2(√5)))))/(25))π

=2π40(1+tan2x)21tanx+tan2xtan3x+tan4xdxUset=tanxtoget210t2+1t4t3+t2t+1dtIget25(5+25)25π

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