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Question Number 201949 by sonukgindia last updated on 16/Dec/23

Answered by Frix last updated on 17/Dec/23

$$n^k\equiv n\mathrm{mod}2024;n\in \{529,737,760,1265,1288,1496\}$$$$\Rightarrow$$$$\mathrm{\Sigma }{n}^n\equiv 3\mathrm{mod}2024$$

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