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Question Number 20198 by Joel577 last updated on 24/Aug/17

$$\mathrm{Find}\mathrm{exact}\mathrm{form}\mathrm{of}$$$$\cos \left({\tan }^{-1}\left(\frac{1}{2}\right)\right)$$

Answered by Tinkutara last updated on 24/Aug/17

$${\tan }^{-1}\left(\frac{1}{2}\right)={\cos }^{-1}\left(\frac{2}{\sqrt{5}}\right)$$$$\therefore \cos \left({\cos }^{-1}\left(\frac{2}{\sqrt{5}}\right)\right)=\frac{2}{\sqrt{5}}$$

Commented by Joel577 last updated on 24/Aug/17

$$thankyouverymuch$$

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