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Question Number 20205 by vivek last updated on 24/Aug/17

$$findthe{sin}^{-1}diferentiation$$

Answered by Joel577 last updated on 24/Aug/17

$$y={\sin }^{-1}\left(x\right)$$$$x=\sin y$$$$\frac{dx}{dy}=\cos y=\sqrt{1-{\sin }^{2}y}$$$$\frac{dy}{dx}=\frac{1}{\cos y}=\frac{1}{\sqrt{1-{\sin }^{2}y}}=\frac{1}{\sqrt{1-x^2}}$$

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