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Question Number 202170 by sonukgindia last updated on 22/Dec/23

Answered by deleteduser1 last updated on 22/Dec/23

112=a2^m ⇒a2^(m−4) =7⇒2^(m−4) =1⇒m=4;a=7 11392=b2^n =2^7 ×89⇒n=7;b=89 (7+89)≡8(mod 4+7);⇒(a+b)≡8(mod (m+n))

112=a2m⇒a2m−4=7⇒2m−4=1⇒m=4;a=711392=b2n=27×89⇒n=7;b=89(7+89)≡8(mod4+7);⇒(a+b)≡8(mod(m+n))

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