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Question Number 202418 by MathematicalUser2357 last updated on 26/Dec/23

Hard integral  ∫∫∫∫∫∫∫∫∫ determinant ((a,b,c),(f,g,h),(j,k,l))dl dk dj dh dg df dc db da=

Hardintegral|abcfghjkl|dldkdjdhdgdfdcdbda=

Answered by Frix last updated on 26/Dec/23

Not hard at all  =((abcfghjkl)/8)(a(gl−hk)−b(fl−hj)+c(fk−gj))

Nothardatall=abcfghjkl8(a(glhk)b(flhj)+c(fkgj))

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