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Question Number 202530 by Calculusboy last updated on 28/Dec/23

Answered by MathematicalUser2357 last updated on 29/Dec/23

$$=\underset{x\to 0}{\lim }\frac{\log {(1+x)}^{1+x}-x}{x^2}$$$$=\frac{1}{2}\underset{x\to 0}{\lim }\left(\frac{{\partial }^2}{{\partial }^{2}x}(\log {(1+x)}^{1+x}-x)\right)$$$$=...(15\sim 30\mathrm{steps})...$$$$=⟨\mathrm{LIMIT}\mathrm{DOES}\mathrm{NOT}\mathrm{CONVERGE}⟩$$

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