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Question Number 202551 by aba last updated on 29/Dec/23

$$\underset{\mathrm{i}=1}{\sum ^{\mathrm{n}}}{(\mathrm{x}+\mathrm{y})}_{\mathrm{i}}={(\mathrm{x}+\mathrm{y})}_1+{(\mathrm{x}+\mathrm{y})}_2+...{(\mathrm{x}+\mathrm{y})}_{\mathrm{n}}$$$$={\mathrm{x}}_1+{\mathrm{y}}_1+{\mathrm{x}}_2+{\mathrm{y}}_2+...+{\mathrm{x}}_{\mathrm{n}}+{\mathrm{y}}_{\mathrm{n}}$$$$\mathrm{please}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{correct}?$$$$$$

Commented by mr W last updated on 29/Dec/23

$$itdependsonwhatyoumeanwith$$$${(x+y)}_i.ifyoumean{(x+y)}_i=x_i+y_i,$$$$then{it}^{\prime }scertainlycorrect.$$

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