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Question Number 202679 by Mingma last updated on 31/Dec/23

Answered by esmaeil last updated on 31/Dec/23

↷→<_(hex) =120→  tan30=(h/(a/2))→h=(((√3)a)/6)  2((a/2)×(((√3)a)/6)×(1/2))=43=(S_(blue) +S_(pink) )→  (√3)a^2 =12×43→a≅17.26→  A_h =17.26×17.26−(2×43)=211.91

↷→<hex=120tan30=ha2h=3a62(a2×3a6×12)=43=(Sblue+Spink)3a2=12×43a17.26Ah=17.26×17.26(2×43)=211.91

Commented by Mingma last updated on 31/Dec/23

Perfect ��

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