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Question Number 202694 by Mingma last updated on 31/Dec/23

Answered by a.lgnaoui last updated on 01/Jan/24

$$\mathrm{\Delta }\mathbf{KTP}$$$$$$

Commented by a.lgnaoui last updated on 01/Jan/24

Answered by mr W last updated on 02/Jan/24

Commented by mr W last updated on 02/Jan/24

$$\mathrm{\Delta }KTP=\mathrm{\Delta }KEM$$$$\Rightarrow \mathrm{\angle }KME=\mathrm{\angle }KPT$$$$\Rightarrow \mathrm{\angle }EFP=\mathrm{\angle }EKM=60°$$$${\mathrm{\Delta }}_{ETP}=\frac{TP\times EF\times \sin \mathrm{\angle }EFP}{2}$$$$=\frac{\sqrt{3}}{4}\times TP\times EF$$$$=\frac{\sqrt{3}}{4}\times \frac{253}{\sqrt{3}}\times 32=2024✓$$

Answered by ajfour last updated on 02/Jan/24

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