place(1→25) in table(5×5)in such away that the sum is constant in all directions. [ ∣×


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Question Number 202750 by esmaeil last updated on 02/Jan/24

$p l a c e (1 \to 25)$ $i n t a b l e (5 \times 5) i n s u c h a w a y t h a t$ $t h e s u m i s c o n s t a n t i n a l l d i r e c t i o n s .$ $[∣ \underline{\bar{\times}} ∣] \to (d i r e c t i o n)$
Commented by esmaeil last updated on 02/Jan/24

$f o r e x a m p l e (3 \times 3)$ $[8] [1] [6]$ $[3] [5] [7]$ $[4] [9] [2]$
	Answered by Rasheed.Sindhi last updated on 02/Jan/24

	$65$ $\begin{array}{cccccc} 17 & 24 & 1 & 8 & 15 & 65 \\ 23 & 5 & 7 & 14 & 16 & 65 \\ 4 & 6 & 13 & 20 & 22 & 65 \\ 10 & 12 & 19 & 21 & 3 & 65 \\ 11 & 18 & 25 & 2 & 9 & 65 \\ 65 & 65 & 65 & 65 & 65 & 65 \end{array}$ $65 a r e s u m s o f r o w s$ $65 a r e s u m s o f c o l u m n s$ $65 a r e s u m s o f d i a g o n a l s$
	Commented by esmaeil last updated on 02/Jan/24

	$⋚$
	Commented by esmaeil last updated on 02/Jan/24

	$i t c a n b e s o l v e d f o r a l l t a b l e s$ $w i t h o d d n u m b e r o f r o w s a n d$ $c o l u m n s .$
	Commented by Rasheed.Sindhi last updated on 02/Jan/24

	$A l s o f o r e v e n o r d e r t h e r e a r e d i f f e r e n t$ $p a t t e r n s / r u l e s .$
	Answered by BaliramKumar last updated on 02/Jan/24

	Commented by BaliramKumar last updated on 02/Jan/24

	$write 1 to 25 continuous and fit same colour box$ $start any number$ $2, 3, 4, 5, . . . . . . . . . 24, 25, 1$ $10, 11, 12, 13, . . . . . . . . . 24, 25, 1 . . . . . . . . 8, 9$
	Commented by esmaeil last updated on 02/Jan/24

	$c l e v e r s o l u t i o n .$ $e x c e l l e n t$
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