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Question Number 202867 by esmaeil last updated on 04/Jan/24

∫_0 ^1 ∫_(2x) ^2 cos(y^2 )dydx

012x2cos(y2)dydx

Answered by MathematicalUser2357 last updated on 06/Jan/24

((sin 229.1831°)/4)≈−0.1892

sin229.1831°40.1892

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