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Question Number 202893 by sonukgindia last updated on 05/Jan/24

Answered by BaliramKumar last updated on 05/Jan/24

$$0.5=h(cot37°-cot41°)$$$$h=2.830km$$

Answered by deleteduser1 last updated on 05/Jan/24

$$\frac{sin\left(139\right)}{g}=\frac{sin\left(4\right)}{0.5}\Rightarrow g=\frac{sin\left(139\right)}{2sin\left(4\right)}$$$$\frac{sin\left(90\right)}{g}=\frac{sin\left(37\right)}{h}\Rightarrow h=gsin\left(37\right)=\frac{sin\left(139\right)sin\left(37\right)}{2sin\left(4\right)}$$$$\approx 2.83km$$

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