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Question Number 202911 by Ari last updated on 05/Jan/24

Answered by deleteduser1 last updated on 05/Jan/24

Commented by deleteduser1 last updated on 05/Jan/24

WLOG,let the side of the square be 1  ((sin 70)/1)=((sin(90))/b)⇒b=(1/(cos(20)))  ((sin(65))/1)=((sin(90))/a)⇒a=(1/(cos(25)))  ⇒cos(25)sin(x)=sin(135−x)cos(20)⇒x=70°

WLOG,letthesideofthesquarebe1sin701=sin(90)bb=1cos(20)sin(65)1=sin(90)aa=1cos(25)cos(25)sin(x)=sin(135x)cos(20)x=70°

Answered by mr W last updated on 05/Jan/24

Commented by mr W last updated on 05/Jan/24

ΔABD≡ΔABC  x=90°−20°=70°

ΔABDΔABCx=90°20°=70°

Commented by deleteduser1 last updated on 05/Jan/24

How did you get ∠ABD=x°?

HowdidyougetABD=x°?

Commented by mr W last updated on 05/Jan/24

∠DAB=∠CAB=45°  AD=AC  ⇒ΔABD≡ΔABC  ⇒∠ABD=∠ABC=x

DAB=CAB=45°AD=ACΔABDΔABCABD=ABC=x

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